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# Copyright (c) 2017 Weitian LI <weitian@aaronly.me>
# MIT license
"""
Solve the Fokker-Planck equation to derive the time evolution
of the electron spectrum (or number density distribution).
"""
import logging
import numpy as np
logger = logging.getLogger(__name__)
def TDMAsolver(a, b, c, d):
"""
Tri-diagonal matrix algorithm (a.k.a Thomas algorithm) solver,
which is much faster than the generic Gaussian elimination algorithm.
a[i]*x[i-1] + b[i]*x[i] + c[i]*x[i+1] = d[i],
where: a[0] = c[N-1] = 0
Example
-------
>>> A = np.array([[10, 2, 0, 0],
[ 3, 10, 4, 0],
[ 0, 1, 7, 5],
[ 0, 0, 3, 4]], dtype=float)
>>> a = np.array([ 3, 1, 3], dtype=float)
>>> b = np.array([10, 10, 7, 4], dtype=float)
>>> c = np.array([ 2, 4, 5 ], dtype=float)
>>> d = np.array([ 3, 4, 5, 6], dtype=float)
>>> print(TDMAsolver(a, b, c, d))
[ 0.14877589 0.75612053 -1.00188324 2.25141243]
# compare against numpy linear algebra library
>>> print(np.linalg.solve(A, d))
[ 0.14877589 0.75612053 -1.00188324 2.25141243]
References
----------
[1] http://en.wikipedia.org/wiki/Tridiagonal_matrix_algorithm
Credit
------
[1] https://gist.github.com/cbellei/8ab3ab8551b8dfc8b081c518ccd9ada9
"""
# Number of equations
nf = len(d)
# Copy the input arrays
ac, bc, cc, dc = map(np.array, (a, b, c, d))
for it in range(1, nf):
mc = ac[it-1] / bc[it-1]
bc[it] -= mc*cc[it-1]
dc[it] -= mc*dc[it-1]
xc = bc
xc[-1] = dc[-1] / bc[-1]
for il in range(nf-2, -1, -1):
xc[il] = (dc[il] - cc[il]*xc[il+1]) / bc[il]
return xc
class FokkerPlanckSolver:
"""
Solve the Fokker-Planck equation:
∂u(x,t) ∂ / ∂u(x) \ u(x,t)
------- = -- | B(x)u(x) + C(x)----- | + Q(x,t) - ------
∂t ∂x \ ∂x / T(x,t)
u(x,t) : distribution/spectrum w.r.t. x at different times
B(x,t) : advection coefficient
C(x,t) : diffusion coefficient (>0)
Q(x,t) : injection coefficient (>=0)
T(x,t) : escape coefficient
NOTE: The no-flux boundary condition is used.
Parameters
----------
xmin, xmax : float
The minimum and maximum bounds of the X (spatial/momentum) axis.
x_np : int
Number of (logarithmic grid) points/cells along the X axis
tstep : float
Specify to use the constant time step for solving the equation.
f_advection : function
Function f(x,t) to calculate the advection coefficient B(x,t)
f_diffusion : function
Function f(x,t) to calculate the diffusion coefficient C(x,t)
f_injection : function
Function f(x,t) to calculate the injection coefficient Q(x,t)
f_escape : optional
Function f(x,t) to calculate the escape coefficient T(x,t)
buffer_np : int, optional
Number of grid points taking as the buffer region near the lower
boundary. The densities within this buffer region will be replaced
by extrapolating an power law to avoid unphysical accumulations.
This fix is ignored if this parameter is not specified.
References
----------
[1] Park & Petrosian 1996, ApJS, 103, 255
http://adsabs.harvard.edu/abs/1996ApJS..103..255P
[2] Donnert & Brunetti 2014, MNRAS, 443, 3564
http://adsabs.harvard.edu/abs/2014MNRAS.443.3564D
"""
def __init__(self, xmin, xmax, x_np, tstep,
f_advection, f_diffusion, f_injection,
f_escape=None, buffer_np=None):
self.xmin = xmin
self.xmax = xmax
self.x_np = x_np
self.tstep = tstep
self.f_advection = f_advection
self.f_diffusion = f_diffusion
self.f_injection = f_injection
self.f_escape = f_escape
self.buffer_np = buffer_np
@property
def x(self):
"""
X values of the adopted logarithmic grid.
"""
grid = np.logspace(np.log10(self.xmin), np.log10(self.xmax),
num=self.x_np)
return grid
@property
def dx(self):
"""
Values of dx[i] on the grid.
dx[i] = (x[i+1] - x[i-1]) / 2
NOTE:
Extrapolate the x grid by 1 point beyond each side, therefore
avoid NaN for the first and last element of dx[i].
Otherwise, the following calculation of tridiagonal coefficients
may be invalid on the boundary elements.
References: Ref.[1],Eq.(8)
"""
x = self.x
# Extrapolate the x grid by 1 point beyond each side
x2 = np.concatenate([
[x[0]**2/x[1]],
x,
[x[-1]**2/x[-2]],
])
dx_ = (x2[2:] - x2[:-2]) / 2
return dx_
@property
def dx_phalf(self):
"""
Values of dx[i+1/2] on the grid.
dx[i+1/2] = x[i+1] - x[i]
Thus the last element is NaN.
References: Ref.[1],Eq.(8)
"""
x = self.x
dx_ = x[1:] - x[:-1]
grid = np.concatenate([dx_, [np.nan]])
return grid
@property
def dx_mhalf(self):
"""
Values of dx[i-1/2] on the grid.
dx[i-1/2] = x[i] - x[i-1]
Thus the first element is NaN.
"""
x = self.x
dx_ = x[1:] - x[:-1]
grid = np.concatenate([[np.nan], dx_])
return grid
@staticmethod
def X_phalf(X):
"""
Calculate the values at midpoints (+1/2) for the given quantity.
X[i+1/2] = (X[i] + X[i+1]) / 2
Thus the last element is NaN.
References: Ref.[1],Eq.(10)
"""
Xmid = (X[1:] + X[:-1]) / 2
return np.concatenate([Xmid, [np.nan]])
@staticmethod
def X_mhalf(X):
"""
Calculate the values at midpoints (-1/2) for the given quantity.
X[i-1/2] = (X[i-1] + X[i]) / 2
Thus the first element is NaN.
"""
Xmid = (X[1:] + X[:-1]) / 2
return np.concatenate([[np.nan], Xmid])
@staticmethod
def W(w):
# References: Ref.[1],Eqs.(27,35)
with np.errstate(invalid="ignore"):
# Ignore NaN's
w = np.abs(w)
mask = (w < 0.1) # Comparison on NaN gives False, as expected
W = np.zeros(w.shape) * np.nan
W[mask] = 1.0 / (1 + w[mask]**2/24 + w[mask]**4/1920)
W[~mask] = (w[~mask] * np.exp(-w[~mask]/2) /
(1 - np.exp(-w[~mask])))
return W
@staticmethod
def bound_w(w, wmin=1e-8, wmax=1e3):
"""
Bound the absolute values of w within [wmin, wmax].
To avoid the underflow/overflow during later W/Wplus/Wminus
calculations.
"""
with np.errstate(invalid="ignore"):
# Ignore NaN's
m1 = (np.abs(w) < wmin)
m2 = (np.abs(w) > wmax)
ww = np.array(w)
ww[m1] = wmin * np.sign(ww[m1])
ww[m2] = wmax * np.sign(ww[m2])
return ww
def Wplus(self, w):
# References: Ref.[1],Eq.(32)
ww = self.bound_w(w)
W = self.W(ww)
Wplus = W * np.exp(ww/2)
return Wplus
def Wminus(self, w):
# References: Ref.[1],Eq.(32)
ww = self.bound_w(w)
W = self.W(ww)
Wminus = W * np.exp(-ww/2)
return Wminus
def tridiagonal_coefs(self, tc, uc):
"""
Calculate the coefficients for the tridiagonal system of linear
equations corresponding to the original Fokker-Planck equation.
-a[i]*u[i-1] + b[i]*u[i] - c[i]*u[i+1] = r[i],
where: a[0] = c[N-1] = 0
NOTE
----
When i=0 or i=N-1, b[i] is invalid due to X[-1/2] or X[N-1/2] are
invalid. Therefore, b[0] and b[N-1] should be alternatively
calculated with (e.g., no-flux) boundary condition considered.
References: Ref.[1],Eqs.(16,18,34)
"""
x = self.x
dx = self.dx
dx_phalf = self.dx_phalf
dx_mhalf = self.dx_mhalf
dt = self.tstep
B = np.array([self.f_advection(x_, tc) for x_ in x])
C = np.array([self.f_diffusion(x_, tc) for x_ in x])
Q = np.array([self.f_injection(x_, tc) for x_ in x])
#
B_phalf = self.X_phalf(B)
B_mhalf = self.X_mhalf(B)
C_phalf = self.X_phalf(C)
C_mhalf = self.X_mhalf(C)
w_phalf = dx_phalf * B_phalf / C_phalf
w_mhalf = dx_mhalf * B_mhalf / C_mhalf
Wplus_phalf = self.Wplus(w_phalf)
Wplus_mhalf = self.Wplus(w_mhalf)
Wminus_phalf = self.Wminus(w_phalf)
Wminus_mhalf = self.Wminus(w_mhalf)
#
a = (dt/dx) * (C_mhalf/dx_mhalf) * Wminus_mhalf
a[0] = 0.0 # Fix a[0] which is NaN
c = (dt/dx) * (C_phalf/dx_phalf) * Wplus_phalf
c[-1] = 0.0 # Fix c[-1] which is NaN
b = 1 + (dt/dx) * ((C_mhalf/dx_mhalf) * Wplus_mhalf +
(C_phalf/dx_phalf) * Wminus_phalf)
# Calculate b[0] & b[-1], considering the no-flux boundary condition
b[0] = 1 + (dt/dx[0]) * (C_phalf[0]/dx_phalf[0])*Wminus_phalf[0]
b[-1] = 1 + (dt/dx[-1]) * (C_mhalf[-1]/dx_mhalf[-1])*Wplus_mhalf[-1]
# Escape from the system
if self.f_escape is not None:
T = np.array([self.f_escape(x_, tc) for x_ in x])
b += dt / T
# Right-hand side
r = dt * Q + uc
return (a, b, c, r)
def fix_boundary(self, uc):
"""
Truncate the lower end (i.e., near the lower boundary) of the
distribution/spectrum and then extrapolate as a power law, in order
to avoid the unphysical pile-up of electrons at the lower regime.
TODO:
Fit a power law to the same number (``buffer_np``) of data points,
then extrapolate it to fix the lower buffer region.
References: Ref.[2],Sec.(3.3)
"""
if self.buffer_np is None:
return uc
uc = np.asarray(uc)
x = self.x
# Calculate the power-law index
xa = x[self.buffer_np]
xb = x[self.buffer_np+1]
ya = uc[self.buffer_np]
yb = uc[self.buffer_np+1]
if ya > 0 and yb > 0:
# Truncate and extrapolate as a power law
s = np.log(yb/ya) / np.log(xb/xa)
uc[:self.buffer_np] = ya * (x[:self.buffer_np] / xa) ** s
return uc
def time_step(self):
"""
Adaptively determine the time step for solving the equation.
TODO/XXX
"""
pass
def solve_step(self, tc, uc):
"""
Solve the Fokker-Planck equation by a single step.
"""
a, b, c, r = self.tridiagonal_coefs(tc=tc, uc=uc)
TDM_a = -a[1:] # Also drop the first element
TDM_b = b
TDM_c = -c[:-1] # Also drop the last element
TDM_rhs = r
t2 = tc + self.tstep
u2 = TDMAsolver(TDM_a, TDM_b, TDM_c, TDM_rhs)
u2 = self.fix_boundary(u2)
# Clear negative number densities
# u2[u2 < 0] = 0
return (t2, u2)
def solve(self, u0, tstart, tstop):
"""
Solve the Fokker-Planck equation from ``tstart`` to ``tstop``,
with initial spectrum/distribution ``u0``.
"""
uc = u0
tc = tstart
logger.info("Solving Fokker-Planck equation: " +
"time: %.3f - %.3f" % (tstart, tstop))
nstep = int((tstop - tc) / self.tstep)
logger.info("Constant time step: %.3f (#%d steps)" %
(self.tstep, nstep))
i = 0
while tc < tstop:
i += 1
logger.debug("[%d/%d] t=%.3f ..." % (i, nstep, tc))
tc, uc = self.solve_step(tc, uc)
return uc
|